Base | Representation |
---|---|
bin | 1001100110011100001010… |
… | …10100100010000110110011 |
3 | 2202202021202122112212010212 |
4 | 10303032011110202012303 |
5 | 10231344334224342042 |
6 | 112522415215014335 |
7 | 4306202031460013 |
oct | 463160524420663 |
9 | 82667678485125 |
10 | 21112001012147 |
11 | 67aa605201091 |
12 | 244b79250a3ab |
13 | ba1b124b9416 |
14 | 52db7d527c43 |
15 | 269289207482 |
hex | 1333855221b3 |
21112001012147 has 2 divisors, whose sum is σ = 21112001012148. Its totient is φ = 21112001012146.
The previous prime is 21112001012093. The next prime is 21112001012149. The reversal of 21112001012147 is 74121010021112.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 21112001012147 - 228 = 21111732576691 is a prime.
Together with 21112001012149, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (21112001012149) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10556000506073 + 10556000506074.
It is an arithmetic number, because the mean of its divisors is an integer number (10556000506074).
Almost surely, 221112001012147 is an apocalyptic number.
21112001012147 is a deficient number, since it is larger than the sum of its proper divisors (1).
21112001012147 is an equidigital number, since it uses as much as digits as its factorization.
21112001012147 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 224, while the sum is 23.
Adding to 21112001012147 its reverse (74121010021112), we get a palindrome (95233011033259).
The spelling of 21112001012147 in words is "twenty-one trillion, one hundred twelve billion, one million, twelve thousand, one hundred forty-seven".
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