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211120022000047 is a prime number
BaseRepresentation
bin110000000000001100110101…
…111010101001000110101111
31000200111212200022212001202211
4300000030311322221012233
5210132442301113000142
62025003111005031251
762316626645622466
oct6000146572510657
91020455608761684
10211120022000047
11612a6553593336
121b818584255527
1390a56c0300b74
143a1c3993cb9dd
151961ab25e7917
hexc00335ea91af

211120022000047 has 2 divisors, whose sum is σ = 211120022000048. Its totient is φ = 211120022000046.

The previous prime is 211120021999961. The next prime is 211120022000051. The reversal of 211120022000047 is 740000220021112.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 211120022000047 - 223 = 211120013611439 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 211120021999991 and 211120022000027.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (211120022003047) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105560011000023 + 105560011000024.

It is an arithmetic number, because the mean of its divisors is an integer number (105560011000024).

Almost surely, 2211120022000047 is an apocalyptic number.

211120022000047 is a deficient number, since it is larger than the sum of its proper divisors (1).

211120022000047 is an equidigital number, since it uses as much as digits as its factorization.

211120022000047 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 448, while the sum is 22.

Adding to 211120022000047 its reverse (740000220021112), we get a palindrome (951120242021159).

The spelling of 211120022000047 in words is "two hundred eleven trillion, one hundred twenty billion, twenty-two million, forty-seven", and thus it is an aban number.