Base | Representation |
---|---|
bin | 110000000000001100110101… |
… | …111010101001000110101111 |
3 | 1000200111212200022212001202211 |
4 | 300000030311322221012233 |
5 | 210132442301113000142 |
6 | 2025003111005031251 |
7 | 62316626645622466 |
oct | 6000146572510657 |
9 | 1020455608761684 |
10 | 211120022000047 |
11 | 612a6553593336 |
12 | 1b818584255527 |
13 | 90a56c0300b74 |
14 | 3a1c3993cb9dd |
15 | 1961ab25e7917 |
hex | c00335ea91af |
211120022000047 has 2 divisors, whose sum is σ = 211120022000048. Its totient is φ = 211120022000046.
The previous prime is 211120021999961. The next prime is 211120022000051. The reversal of 211120022000047 is 740000220021112.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 211120022000047 - 223 = 211120013611439 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 211120021999991 and 211120022000027.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (211120022003047) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105560011000023 + 105560011000024.
It is an arithmetic number, because the mean of its divisors is an integer number (105560011000024).
Almost surely, 2211120022000047 is an apocalyptic number.
211120022000047 is a deficient number, since it is larger than the sum of its proper divisors (1).
211120022000047 is an equidigital number, since it uses as much as digits as its factorization.
211120022000047 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 448, while the sum is 22.
Adding to 211120022000047 its reverse (740000220021112), we get a palindrome (951120242021159).
The spelling of 211120022000047 in words is "two hundred eleven trillion, one hundred twenty billion, twenty-two million, forty-seven", and thus it is an aban number.
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