21112012219973 has 2 divisors, whose sum is σ = 21112012219974. Its totient is φ = 21112012219972.

The previous prime is 21112012219829. The next prime is 21112012219993. The reversal of 21112012219973 is 37991221021112.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 18818747211364 + 2293265008609 = 4338058^2 + 1514353^2 .

It is a cyclic number.

It is not a de Polignac number, because 21112012219973 - 2⁸ = 21112012219717 is a prime.

It is a super-3 number, since 3×21112012219973³ (a number of 41 digits) contains 333 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 21112012219973.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (21112012219993) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10556006109986 + 10556006109987.

It is an arithmetic number, because the mean of its divisors is an integer number (10556006109987).

Almost surely, 2^{21112012219973} is an apocalyptic number.

It is an amenable number.

21112012219973 is a deficient number, since it is larger than the sum of its proper divisors (1).

21112012219973 is an equidigital number, since it uses as much as digits as its factorization.

21112012219973 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 27216, while the sum is 41.

The spelling of 21112012219973 in words is "twenty-one trillion, one hundred twelve billion, twelve million, two hundred nineteen thousand, nine hundred seventy-three".