Base | Representation |
---|---|
bin | 1100010010011111001… |
… | …0101100111011010011 |
3 | 202011221101102000201202 |
4 | 3010213302230323103 |
5 | 11424333434001042 |
6 | 240553155421415 |
7 | 21152526614651 |
oct | 3044762547323 |
9 | 664841360652 |
10 | 211121000147 |
11 | 81599334212 |
12 | 34abbbb486b |
13 | 16ba7330a35 |
14 | a30b08bdd1 |
15 | 5759965632 |
hex | 3127caced3 |
211121000147 has 2 divisors, whose sum is σ = 211121000148. Its totient is φ = 211121000146.
The previous prime is 211121000099. The next prime is 211121000159. The reversal of 211121000147 is 741000121112.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 211121000147 - 210 = 211120999123 is a prime.
It is not a weakly prime, because it can be changed into another prime (211121000047) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105560500073 + 105560500074.
It is an arithmetic number, because the mean of its divisors is an integer number (105560500074).
Almost surely, 2211121000147 is an apocalyptic number.
211121000147 is a deficient number, since it is larger than the sum of its proper divisors (1).
211121000147 is an equidigital number, since it uses as much as digits as its factorization.
211121000147 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 112, while the sum is 20.
Adding to 211121000147 its reverse (741000121112), we get a palindrome (952121121259).
The spelling of 211121000147 in words is "two hundred eleven billion, one hundred twenty-one million, one hundred forty-seven", and thus it is an aban number.
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