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211121000147 is a prime number
BaseRepresentation
bin1100010010011111001…
…0101100111011010011
3202011221101102000201202
43010213302230323103
511424333434001042
6240553155421415
721152526614651
oct3044762547323
9664841360652
10211121000147
1181599334212
1234abbbb486b
1316ba7330a35
14a30b08bdd1
155759965632
hex3127caced3

211121000147 has 2 divisors, whose sum is σ = 211121000148. Its totient is φ = 211121000146.

The previous prime is 211121000099. The next prime is 211121000159. The reversal of 211121000147 is 741000121112.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 211121000147 - 210 = 211120999123 is a prime.

It is not a weakly prime, because it can be changed into another prime (211121000047) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105560500073 + 105560500074.

It is an arithmetic number, because the mean of its divisors is an integer number (105560500074).

Almost surely, 2211121000147 is an apocalyptic number.

211121000147 is a deficient number, since it is larger than the sum of its proper divisors (1).

211121000147 is an equidigital number, since it uses as much as digits as its factorization.

211121000147 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 112, while the sum is 20.

Adding to 211121000147 its reverse (741000121112), we get a palindrome (952121121259).

The spelling of 211121000147 in words is "two hundred eleven billion, one hundred twenty-one million, one hundred forty-seven", and thus it is an aban number.