Base | Representation |
---|---|
bin | 11110101110001101111… |
… | …011011001010100100001 |
3 | 21110211101212021021110201 |
4 | 132232031323121110201 |
5 | 234042224241200001 |
6 | 4253513155225201 |
7 | 305346516520612 |
oct | 36561573312441 |
9 | 7424355237421 |
10 | 2111210100001 |
11 | 7443a5075a42 |
12 | 2a11bbba8201 |
13 | 124117680982 |
14 | 7427c671c09 |
15 | 39db6458501 |
hex | 1eb8ded9521 |
2111210100001 has 2 divisors, whose sum is σ = 2111210100002. Its totient is φ = 2111210100000.
The previous prime is 2111210099993. The next prime is 2111210100031. The reversal of 2111210100001 is 1000010121112.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1476079203600 + 635130896401 = 1214940^2 + 796951^2 .
It is a cyclic number.
It is not a de Polignac number, because 2111210100001 - 23 = 2111210099993 is a prime.
It is not a weakly prime, because it can be changed into another prime (2111210100031) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1055605050000 + 1055605050001.
It is an arithmetic number, because the mean of its divisors is an integer number (1055605050001).
Almost surely, 22111210100001 is an apocalyptic number.
It is an amenable number.
2111210100001 is a deficient number, since it is larger than the sum of its proper divisors (1).
2111210100001 is an equidigital number, since it uses as much as digits as its factorization.
2111210100001 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 4, while the sum is 10.
Adding to 2111210100001 its reverse (1000010121112), we get a palindrome (3111220221113).
The spelling of 2111210100001 in words is "two trillion, one hundred eleven billion, two hundred ten million, one hundred thousand, one".
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