Base | Representation |
---|---|
bin | 1001100110011100010110… |
… | …10010101110010001101111 |
3 | 2202202022000122001222102101 |
4 | 10303032023102232101233 |
5 | 10231400040401413012 |
6 | 112522433154235531 |
7 | 4306204356166555 |
oct | 463161322562157 |
9 | 82668018058371 |
10 | 21112101201007 |
11 | 67aa6568114a3 |
12 | 244b7bbb85ba7 |
13 | ba1b2a197b7b |
14 | 52db8c967bd5 |
15 | 269292de7d57 |
hex | 13338b4ae46f |
21112101201007 has 2 divisors, whose sum is σ = 21112101201008. Its totient is φ = 21112101201006.
The previous prime is 21112101200999. The next prime is 21112101201043. The reversal of 21112101201007 is 70010210121112.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 21112101201007 - 23 = 21112101200999 is a prime.
It is a super-2 number, since 2×211121012010072 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (21112101201077) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10556050600503 + 10556050600504.
It is an arithmetic number, because the mean of its divisors is an integer number (10556050600504).
Almost surely, 221112101201007 is an apocalyptic number.
21112101201007 is a deficient number, since it is larger than the sum of its proper divisors (1).
21112101201007 is an equidigital number, since it uses as much as digits as its factorization.
21112101201007 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 56, while the sum is 19.
Adding to 21112101201007 its reverse (70010210121112), we get a palindrome (91122311322119).
The spelling of 21112101201007 in words is "twenty-one trillion, one hundred twelve billion, one hundred one million, two hundred one thousand, seven".
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