211121100000113 has 2 divisors, whose sum is σ = 211121100000114. Its totient is φ = 211121100000112.

The previous prime is 211121100000103. The next prime is 211121100000127. The reversal of 211121100000113 is 311000001121112.

It is an a-pointer prime, because the next prime (211121100000127) can be obtained adding 211121100000113 to its sum of digits (14).

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 201863058453904 + 9258041546209 = 14207852^2 + 3042703^2 .

It is a cyclic number.

It is not a de Polignac number, because 211121100000113 - 2⁸ = 211121099999857 is a prime.

It is not a weakly prime, because it can be changed into another prime (211121100000103) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105560550000056 + 105560550000057.

It is an arithmetic number, because the mean of its divisors is an integer number (105560550000057).

Almost surely, 2^{211121100000113} is an apocalyptic number.

It is an amenable number.

211121100000113 is a deficient number, since it is larger than the sum of its proper divisors (1).

211121100000113 is an equidigital number, since it uses as much as digits as its factorization.

211121100000113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 12, while the sum is 14.

Adding to 211121100000113 its reverse (311000001121112), we get a palindrome (522121101121225).

The spelling of 211121100000113 in words is "two hundred eleven trillion, one hundred twenty-one billion, one hundred million, one hundred thirteen", and thus it is an aban number.