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211121111210213 is a prime number
BaseRepresentation
bin110000000000001101110110…
…110101101001100011100101
31000200111222111020101200020002
4300000031312311221203211
5210133002013432211323
62025003411034351045
762316665643016361
oct6000156665514345
91020458436350202
10211121111210213
11612a6a623a9026
121b818828b8b485
1390a5834b74619
143a1c45dd1c2a1
151961b2804b828
hexc00376d698e5

211121111210213 has 2 divisors, whose sum is σ = 211121111210214. Its totient is φ = 211121111210212.

The previous prime is 211121111210209. The next prime is 211121111210327. The reversal of 211121111210213 is 312012111121112.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 195220332904129 + 15900778306084 = 13972127^2 + 3987578^2 .

It is a cyclic number.

It is not a de Polignac number, because 211121111210213 - 22 = 211121111210209 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (211121111110213) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105560555605106 + 105560555605107.

It is an arithmetic number, because the mean of its divisors is an integer number (105560555605107).

Almost surely, 2211121111210213 is an apocalyptic number.

It is an amenable number.

211121111210213 is a deficient number, since it is larger than the sum of its proper divisors (1).

211121111210213 is an equidigital number, since it uses as much as digits as its factorization.

211121111210213 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 48, while the sum is 20.

Adding to 211121111210213 its reverse (312012111121112), we get a palindrome (523133222331325).

The spelling of 211121111210213 in words is "two hundred eleven trillion, one hundred twenty-one billion, one hundred eleven million, two hundred ten thousand, two hundred thirteen".