211121121110117 has 2 divisors, whose sum is σ = 211121121110118. Its totient is φ = 211121121110116.

The previous prime is 211121121110047. The next prime is 211121121110171. The reversal of 211121121110117 is 711011121121112.

Together with next prime (211121121110171) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 183577948220836 + 27543172889281 = 13549094^2 + 5248159^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-211121121110117 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 211121121110092 and 211121121110101.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (211121121110617) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105560560555058 + 105560560555059.

It is an arithmetic number, because the mean of its divisors is an integer number (105560560555059).

Almost surely, 2^{211121121110117} is an apocalyptic number.

It is an amenable number.

211121121110117 is a deficient number, since it is larger than the sum of its proper divisors (1).

211121121110117 is an equidigital number, since it uses as much as digits as its factorization.

211121121110117 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 56, while the sum is 23.

Adding to 211121121110117 its reverse (711011121121112), we get a palindrome (922132242231229).

The spelling of 211121121110117 in words is "two hundred eleven trillion, one hundred twenty-one billion, one hundred twenty-one million, one hundred ten thousand, one hundred seventeen".