Base | Representation |
---|---|
bin | 110000000000001101111100… |
… | …001000110011010101101111 |
3 | 1000200111222201102200121112212 |
4 | 300000031330020303111233 |
5 | 210133002204212221403 |
6 | 2025003423532121035 |
7 | 62320001102510213 |
oct | 6000157410632557 |
9 | 1020458642617485 |
10 | 211121200117103 |
11 | 612a6aa86030a1 |
12 | 1b81885290617b |
13 | 90a584a402b53 |
14 | 3a1c46ba62943 |
15 | 1961b30c5e4d8 |
hex | c0037c23356f |
211121200117103 has 2 divisors, whose sum is σ = 211121200117104. Its totient is φ = 211121200117102.
The previous prime is 211121200117099. The next prime is 211121200117117. The reversal of 211121200117103 is 301711002121112.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 211121200117103 - 22 = 211121200117099 is a prime.
It is a super-2 number, since 2×2111212001171032 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (211121200117183) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105560600058551 + 105560600058552.
It is an arithmetic number, because the mean of its divisors is an integer number (105560600058552).
Almost surely, 2211121200117103 is an apocalyptic number.
211121200117103 is a deficient number, since it is larger than the sum of its proper divisors (1).
211121200117103 is an equidigital number, since it uses as much as digits as its factorization.
211121200117103 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 168, while the sum is 23.
Adding to 211121200117103 its reverse (301711002121112), we get a palindrome (512832202238215).
The spelling of 211121200117103 in words is "two hundred eleven trillion, one hundred twenty-one billion, two hundred million, one hundred seventeen thousand, one hundred three".
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