Base | Representation |
---|---|
bin | 1001100110011100011000… |
… | …11010011110110101110011 |
3 | 2202202022001221110200110021 |
4 | 10303032030122132311303 |
5 | 10231400110210342042 |
6 | 112522435105344311 |
7 | 4306205005114543 |
oct | 463161432366563 |
9 | 82668057420407 |
10 | 21112120012147 |
11 | 67aa66639a59a |
12 | 244b806338097 |
13 | ba1b31053118 |
14 | 52db91263323 |
15 | 2692948b1867 |
hex | 13338c69ed73 |
21112120012147 has 2 divisors, whose sum is σ = 21112120012148. Its totient is φ = 21112120012146.
The previous prime is 21112120012099. The next prime is 21112120012229. The reversal of 21112120012147 is 74121002121112.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-21112120012147 is a prime.
It is a super-2 number, since 2×211121200121472 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (21112120012847) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10556060006073 + 10556060006074.
It is an arithmetic number, because the mean of its divisors is an integer number (10556060006074).
Almost surely, 221112120012147 is an apocalyptic number.
21112120012147 is a deficient number, since it is larger than the sum of its proper divisors (1).
21112120012147 is an equidigital number, since it uses as much as digits as its factorization.
21112120012147 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 448, while the sum is 25.
Adding to 21112120012147 its reverse (74121002121112), we get a palindrome (95233122133259).
The spelling of 21112120012147 in words is "twenty-one trillion, one hundred twelve billion, one hundred twenty million, twelve thousand, one hundred forty-seven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.072 sec. • engine limits •