Base | Representation |
---|---|
bin | 11110101110001110000… |
… | …011000110110000111011 |
3 | 21110211102000001221221222 |
4 | 132232032003012300323 |
5 | 234042230300334042 |
6 | 4253513310422255 |
7 | 305346542636303 |
oct | 36561603066073 |
9 | 7424360057858 |
10 | 2111212121147 |
11 | 7443a6226508 |
12 | 2a120080198b |
13 | 124117c0a90c |
14 | 7427ca3a603 |
15 | 39db67072d2 |
hex | 1eb8e0c6c3b |
2111212121147 has 2 divisors, whose sum is σ = 2111212121148. Its totient is φ = 2111212121146.
The previous prime is 2111212121087. The next prime is 2111212121149. The reversal of 2111212121147 is 7411212121112.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-2111212121147 is a prime.
Together with 2111212121149, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (2111212121149) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1055606060573 + 1055606060574.
It is an arithmetic number, because the mean of its divisors is an integer number (1055606060574).
Almost surely, 22111212121147 is an apocalyptic number.
2111212121147 is a deficient number, since it is larger than the sum of its proper divisors (1).
2111212121147 is an equidigital number, since it uses as much as digits as its factorization.
2111212121147 is an evil number, because the sum of its binary digits is even.
The product of its digits is 448, while the sum is 26.
Adding to 2111212121147 its reverse (7411212121112), we get a palindrome (9522424242259).
The spelling of 2111212121147 in words is "two trillion, one hundred eleven billion, two hundred twelve million, one hundred twenty-one thousand, one hundred forty-seven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.066 sec. • engine limits •