Base | Representation |
---|---|
bin | 110000000000001110110001… |
… | …110001101010001111101011 |
3 | 1000200112002001011000102112022 |
4 | 300000032301301222033223 |
5 | 210133011030101121303 |
6 | 2025004053120135055 |
7 | 62320032310533341 |
oct | 6000166161521753 |
9 | 1020462034012468 |
10 | 211122100020203 |
11 | 612a741a579669 |
12 | 1b818a6416748b |
13 | 90a59619943a8 |
14 | 3a1c515395991 |
15 | 1961b84c6c438 |
hex | c003b1c6a3eb |
211122100020203 has 2 divisors, whose sum is σ = 211122100020204. Its totient is φ = 211122100020202.
The previous prime is 211122100020163. The next prime is 211122100020211. The reversal of 211122100020203 is 302020001221112.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 211122100020203 - 214 = 211122100003819 is a prime.
It is a super-2 number, since 2×2111221000202032 (a number of 29 digits) contains 22 as substring.
It is a Sophie Germain prime.
It is not a weakly prime, because it can be changed into another prime (211122100022203) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105561050010101 + 105561050010102.
It is an arithmetic number, because the mean of its divisors is an integer number (105561050010102).
Almost surely, 2211122100020203 is an apocalyptic number.
211122100020203 is a deficient number, since it is larger than the sum of its proper divisors (1).
211122100020203 is an equidigital number, since it uses as much as digits as its factorization.
211122100020203 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 96, while the sum is 17.
Adding to 211122100020203 its reverse (302020001221112), we get a palindrome (513142101241315).
The spelling of 211122100020203 in words is "two hundred eleven trillion, one hundred twenty-two billion, one hundred million, twenty thousand, two hundred three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.089 sec. • engine limits •