Base | Representation |
---|---|
bin | 10011101010011001… |
… | …001010001011001001 |
3 | 2000111100120122021022 |
4 | 103222121022023021 |
5 | 321214224124001 |
6 | 13410542322225 |
7 | 1345116604154 |
oct | 235231121311 |
9 | 60440518238 |
10 | 21112333001 |
11 | 8a543a82a1 |
12 | 4112589375 |
13 | 1cb5c86046 |
14 | 1043d14c9b |
15 | 83873b11b |
hex | 4ea64a2c9 |
21112333001 has 2 divisors, whose sum is σ = 21112333002. Its totient is φ = 21112333000.
The previous prime is 21112332973. The next prime is 21112333003. The reversal of 21112333001 is 10033321112.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 12393255625 + 8719077376 = 111325^2 + 93376^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-21112333001 is a prime.
It is a super-2 number, since 2×211123330012 (a number of 21 digits) contains 22 as substring.
Together with 21112333003, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (21112333003) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10556166500 + 10556166501.
It is an arithmetic number, because the mean of its divisors is an integer number (10556166501).
Almost surely, 221112333001 is an apocalyptic number.
It is an amenable number.
21112333001 is a deficient number, since it is larger than the sum of its proper divisors (1).
21112333001 is an equidigital number, since it uses as much as digits as its factorization.
21112333001 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 108, while the sum is 17.
Adding to 21112333001 its reverse (10033321112), we get a palindrome (31145654113).
The spelling of 21112333001 in words is "twenty-one billion, one hundred twelve million, three hundred thirty-three thousand, one".
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