Base | Representation |
---|---|
bin | 10011101010011001… |
… | …011111101100001011 |
3 | 2000111100202010011101 |
4 | 103222121133230023 |
5 | 321214234434011 |
6 | 13410544242231 |
7 | 1345120422124 |
oct | 235231375413 |
9 | 60440663141 |
10 | 21112421131 |
11 | 8a5445852a |
12 | 4112610377 |
13 | 1cb5cb71a9 |
14 | 1043d3904b |
15 | 8387572c1 |
hex | 4ea65fb0b |
21112421131 has 2 divisors, whose sum is σ = 21112421132. Its totient is φ = 21112421130.
The previous prime is 21112421101. The next prime is 21112421147. The reversal of 21112421131 is 13112421112.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 21112421131 - 27 = 21112421003 is a prime.
It is a super-2 number, since 2×211124211312 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 21112421099 and 21112421108.
It is not a weakly prime, because it can be changed into another prime (21112421101) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10556210565 + 10556210566.
It is an arithmetic number, because the mean of its divisors is an integer number (10556210566).
Almost surely, 221112421131 is an apocalyptic number.
21112421131 is a deficient number, since it is larger than the sum of its proper divisors (1).
21112421131 is an equidigital number, since it uses as much as digits as its factorization.
21112421131 is an evil number, because the sum of its binary digits is even.
The product of its digits is 96, while the sum is 19.
Subtracting from 21112421131 its sum of digits (19), we obtain a palindrome (21112421112).
Adding to 21112421131 its reverse (13112421112), we get a palindrome (34224842243).
It can be divided in two parts, 2111 and 2421131, that added together give a palindrome (2423242).
The spelling of 21112421131 in words is "twenty-one billion, one hundred twelve million, four hundred twenty-one thousand, one hundred thirty-one".
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