Base | Representation |
---|---|
bin | 10011101010011001… |
… | …100111100111100011 |
3 | 2000111100210202201001 |
4 | 103222121213213203 |
5 | 321214242003403 |
6 | 13410545052431 |
7 | 1345120615603 |
oct | 235231474743 |
9 | 60440722631 |
10 | 21112453603 |
11 | 8a5447a96a |
12 | 4112627117 |
13 | 1cb5cc8bc7 |
14 | 1043d46c03 |
15 | 838761c1d |
hex | 4ea6679e3 |
21112453603 has 2 divisors, whose sum is σ = 21112453604. Its totient is φ = 21112453602.
The previous prime is 21112453489. The next prime is 21112453631. The reversal of 21112453603 is 30635421112.
It is an a-pointer prime, because the next prime (21112453631) can be obtained adding 21112453603 to its sum of digits (28).
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-21112453603 is a prime.
It is a super-3 number, since 3×211124536033 (a number of 32 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (21112453693) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10556226801 + 10556226802.
It is an arithmetic number, because the mean of its divisors is an integer number (10556226802).
Almost surely, 221112453603 is an apocalyptic number.
21112453603 is a deficient number, since it is larger than the sum of its proper divisors (1).
21112453603 is an equidigital number, since it uses as much as digits as its factorization.
21112453603 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4320, while the sum is 28.
Adding to 21112453603 its reverse (30635421112), we get a palindrome (51747874715).
The spelling of 21112453603 in words is "twenty-one billion, one hundred twelve million, four hundred fifty-three thousand, six hundred three".
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