Base | Representation |
---|---|
bin | 1001100110011110000010… |
… | …00011101100101101100111 |
3 | 2202202101100111101220110111 |
4 | 10303033001003230231213 |
5 | 10231403412311411403 |
6 | 112523102500033451 |
7 | 4306235621265046 |
oct | 463170103545547 |
9 | 82671314356414 |
10 | 21113003232103 |
11 | 67aaa79a00842 |
12 | 244ba12092887 |
13 | ba1c42022b93 |
14 | 52dc3669255d |
15 | 2692e71c656d |
hex | 1333c10ecb67 |
21113003232103 has 2 divisors, whose sum is σ = 21113003232104. Its totient is φ = 21113003232102.
The previous prime is 21113003232073. The next prime is 21113003232109. The reversal of 21113003232103 is 30123230031112.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-21113003232103 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (21113003232109) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10556501616051 + 10556501616052.
It is an arithmetic number, because the mean of its divisors is an integer number (10556501616052).
Almost surely, 221113003232103 is an apocalyptic number.
21113003232103 is a deficient number, since it is larger than the sum of its proper divisors (1).
21113003232103 is an equidigital number, since it uses as much as digits as its factorization.
21113003232103 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 648, while the sum is 22.
Adding to 21113003232103 its reverse (30123230031112), we get a palindrome (51236233263215).
The spelling of 21113003232103 in words is "twenty-one trillion, one hundred thirteen billion, three million, two hundred thirty-two thousand, one hundred three".
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