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21113014303 is a prime number
BaseRepresentation
bin10011101010011011…
…110000100000011111
32000111101212020211201
4103222123300200133
5321214412424203
613411005100331
71345125442363
oct235233604037
960441766751
1021113014303
118a54823157
1241128576a7
131cb6164194
1410440512a3
15838822e1d
hex4ea6f081f

21113014303 has 2 divisors, whose sum is σ = 21113014304. Its totient is φ = 21113014302.

The previous prime is 21113014291. The next prime is 21113014309. The reversal of 21113014303 is 30341031112.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-21113014303 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (21113014309) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10556507151 + 10556507152.

It is an arithmetic number, because the mean of its divisors is an integer number (10556507152).

Almost surely, 221113014303 is an apocalyptic number.

21113014303 is a deficient number, since it is larger than the sum of its proper divisors (1).

21113014303 is an equidigital number, since it uses as much as digits as its factorization.

21113014303 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 216, while the sum is 19.

Adding to 21113014303 its reverse (30341031112), we get a palindrome (51454045415).

The spelling of 21113014303 in words is "twenty-one billion, one hundred thirteen million, fourteen thousand, three hundred three".