21113100414433 has 2 divisors, whose sum is σ = 21113100414434. Its totient is φ = 21113100414432.

The previous prime is 21113100414407. The next prime is 21113100414449. The reversal of 21113100414433 is 33441400131112.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 19944870177024 + 1168230237409 = 4465968^2 + 1080847^2 .

It is a cyclic number.

It is not a de Polignac number, because 21113100414433 - 2²¹ = 21113098317281 is a prime.

It is a super-3 number, since 3×21113100414433³ (a number of 41 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is not a weakly prime, because it can be changed into another prime (21113100414493) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10556550207216 + 10556550207217.

It is an arithmetic number, because the mean of its divisors is an integer number (10556550207217).

Almost surely, 2^{21113100414433} is an apocalyptic number.

It is an amenable number.

21113100414433 is a deficient number, since it is larger than the sum of its proper divisors (1).

21113100414433 is an equidigital number, since it uses as much as digits as its factorization.

21113100414433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3456, while the sum is 28.

Adding to 21113100414433 its reverse (33441400131112), we get a palindrome (54554500545545).

The spelling of 21113100414433 in words is "twenty-one trillion, one hundred thirteen billion, one hundred million, four hundred fourteen thousand, four hundred thirty-three".