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21113100414407 is a prime number
BaseRepresentation
bin1001100110011110001101…
…10110011010110111000111
32202202101121021021021112002
410303033012312122313013
510231404112201230112
6112523120251015515
74306241211313301
oct463170666326707
982671537237462
1021113100414407
1168000198482a1
12244ba3a73a59b
13ba1c591bacc1
1452dc4554c971
152693009c11c2
hex1333c6d9adc7

21113100414407 has 2 divisors, whose sum is σ = 21113100414408. Its totient is φ = 21113100414406.

The previous prime is 21113100414359. The next prime is 21113100414433. The reversal of 21113100414407 is 70441400131112.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 21113100414407 - 214 = 21113100398023 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 21113100414407.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (21113100416407) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10556550207203 + 10556550207204.

It is an arithmetic number, because the mean of its divisors is an integer number (10556550207204).

Almost surely, 221113100414407 is an apocalyptic number.

21113100414407 is a deficient number, since it is larger than the sum of its proper divisors (1).

21113100414407 is an equidigital number, since it uses as much as digits as its factorization.

21113100414407 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2688, while the sum is 29.

Adding to 21113100414407 its reverse (70441400131112), we get a palindrome (91554500545519).

The spelling of 21113100414407 in words is "twenty-one trillion, one hundred thirteen billion, one hundred million, four hundred fourteen thousand, four hundred seven".