Base | Representation |
---|---|
bin | 1001100110011110001101… |
… | …10110011010110111000111 |
3 | 2202202101121021021021112002 |
4 | 10303033012312122313013 |
5 | 10231404112201230112 |
6 | 112523120251015515 |
7 | 4306241211313301 |
oct | 463170666326707 |
9 | 82671537237462 |
10 | 21113100414407 |
11 | 68000198482a1 |
12 | 244ba3a73a59b |
13 | ba1c591bacc1 |
14 | 52dc4554c971 |
15 | 2693009c11c2 |
hex | 1333c6d9adc7 |
21113100414407 has 2 divisors, whose sum is σ = 21113100414408. Its totient is φ = 21113100414406.
The previous prime is 21113100414359. The next prime is 21113100414433. The reversal of 21113100414407 is 70441400131112.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 21113100414407 - 214 = 21113100398023 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 21113100414407.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (21113100416407) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10556550207203 + 10556550207204.
It is an arithmetic number, because the mean of its divisors is an integer number (10556550207204).
Almost surely, 221113100414407 is an apocalyptic number.
21113100414407 is a deficient number, since it is larger than the sum of its proper divisors (1).
21113100414407 is an equidigital number, since it uses as much as digits as its factorization.
21113100414407 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2688, while the sum is 29.
Adding to 21113100414407 its reverse (70441400131112), we get a palindrome (91554500545519).
The spelling of 21113100414407 in words is "twenty-one trillion, one hundred thirteen billion, one hundred million, four hundred fourteen thousand, four hundred seven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.077 sec. • engine limits •