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21113112014 = 2131577139661
BaseRepresentation
bin10011101010011100…
…001000010111001110
32000111102001012212122
4103222130020113032
5321214424041024
613411011132542
71345126330301
oct235234102716
960442035778
1021113112014
118a5488a605
1241128a4152
131cb61997b7
141044078b38
15838841d5e
hex4ea7085ce

21113112014 has 16 divisors (see below), whose sum is σ = 31966955856. Its totient is φ = 10457740800.

The previous prime is 21113112001. The next prime is 21113112019. The reversal of 21113112014 is 41021131112.

It is a super-2 number, since 2×211131120142 (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 21113111983 and 21113112001.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (21113112019) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 81344 + ... + 221004.

It is an arithmetic number, because the mean of its divisors is an integer number (1997934741).

Almost surely, 221113112014 is an apocalyptic number.

21113112014 is a deficient number, since it is larger than the sum of its proper divisors (10853843842).

21113112014 is a wasteful number, since it uses less digits than its factorization.

21113112014 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 140371.

The product of its (nonzero) digits is 48, while the sum is 17.

Adding to 21113112014 its reverse (41021131112), we get a palindrome (62134243126).

The spelling of 21113112014 in words is "twenty-one billion, one hundred thirteen million, one hundred twelve thousand, fourteen".

Divisors: 1 2 131 262 577 1154 75587 139661 151174 279322 18295591 36591182 80584397 161168794 10556556007 21113112014