Base | Representation |
---|---|
bin | 1100010010100001100… |
… | …1010100010101000101 |
3 | 202011222002110022200201 |
4 | 3010220121110111011 |
5 | 11424344031414023 |
6 | 240554200410501 |
7 | 21153011635456 |
oct | 3045031242505 |
9 | 664862408621 |
10 | 211131123013 |
11 | 815a4018718 |
12 | 34b03476a31 |
13 | 16ba94664b5 |
14 | a30c56512d |
15 | 575a7b4bad |
hex | 3128654545 |
211131123013 has 2 divisors, whose sum is σ = 211131123014. Its totient is φ = 211131123012.
The previous prime is 211131122971. The next prime is 211131123017. The reversal of 211131123013 is 310321131112.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 142013661409 + 69117461604 = 376847^2 + 262902^2 .
It is a cyclic number.
It is not a de Polignac number, because 211131123013 - 217 = 211130991941 is a prime.
It is a super-2 number, since 2×2111311230132 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (211131123017) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105565561506 + 105565561507.
It is an arithmetic number, because the mean of its divisors is an integer number (105565561507).
Almost surely, 2211131123013 is an apocalyptic number.
It is an amenable number.
211131123013 is a deficient number, since it is larger than the sum of its proper divisors (1).
211131123013 is an equidigital number, since it uses as much as digits as its factorization.
211131123013 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 108, while the sum is 19.
Adding to 211131123013 its reverse (310321131112), we get a palindrome (521452254125).
The spelling of 211131123013 in words is "two hundred eleven billion, one hundred thirty-one million, one hundred twenty-three thousand, thirteen".
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