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211131233100000 = 253355172270577
BaseRepresentation
bin110000000000010111010010…
…001001100110000011100000
31000200112221121122111221201000
4300000113102021212003200
5210133133231133200000
62025012203253512000
762320504530453213
oct6000272211460340
91020487548457630
10211131233100000
11613002869a56a4
121b81a792942600
1390a6788b9ac15
143a1cb4032d77a
15196201b985000
hexc005d22660e0

211131233100000 has 864 divisors, whose sum is σ = 817642839071520. Its totient is φ = 52989603840000.

The previous prime is 211131233099987. The next prime is 211131233100001. The reversal of 211131233100000 is 1332131112.

211131233100000 is a `hidden beast` number, since 21 + 1 + 1 + 312 + 331 + 0 + 0 + 0 + 0 + 0 = 666.

It is a tau number, because it is divible by the number of its divisors (864).

It is a super-2 number, since 2×2111312331000002 (a number of 29 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (211131233100001) by changing a digit.

It is a polite number, since it can be written in 143 ways as a sum of consecutive naturals, for example, 780164712 + ... + 780435288.

It is an arithmetic number, because the mean of its divisors is an integer number (946345878555).

Almost surely, 2211131233100000 is an apocalyptic number.

211131233100000 is a gapful number since it is divisible by the number (20) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 211131233100000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (408821419535760).

211131233100000 is an abundant number, since it is smaller than the sum of its proper divisors (606511605971520).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

211131233100000 is an equidigital number, since it uses as much as digits as its factorization.

211131233100000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 270655 (or 270604 counting only the distinct ones).

The product of its (nonzero) digits is 108, while the sum is 18.

Adding to 211131233100000 its reverse (1332131112), we get a palindrome (211132565231112).

The spelling of 211131233100000 in words is "two hundred eleven trillion, one hundred thirty-one billion, two hundred thirty-three million, one hundred thousand".