Base | Representation |
---|---|
bin | 11110101110010100000… |
… | …011111011111000100100 |
3 | 21110211200000220020111121 |
4 | 132232110003323320210 |
5 | 234042432112031040 |
6 | 4253531312543324 |
7 | 305352206260525 |
oct | 36562403737044 |
9 | 7424600806447 |
10 | 2111313002020 |
11 | 744448169832 |
12 | 2a122a551b44 |
13 | 124132a9c341 |
14 | 7428c1ba84c |
15 | 39dc04d2c4a |
hex | 1eb940fbe24 |
2111313002020 has 24 divisors (see below), whose sum is σ = 4434224856768. Its totient is φ = 844436143200.
The previous prime is 2111313001937. The next prime is 2111313002033. The reversal of 2111313002020 is 202003131112.
It is a junction number, because it is equal to n+sod(n) for n = 2111313001985 and 2111313002003.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 5371536 + ... + 5751175.
It is an arithmetic number, because the mean of its divisors is an integer number (184759369032).
Almost surely, 22111313002020 is an apocalyptic number.
2111313002020 is a gapful number since it is divisible by the number (20) formed by its first and last digit.
It is an amenable number.
2111313002020 is an abundant number, since it is smaller than the sum of its proper divisors (2322911854748).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
2111313002020 is a wasteful number, since it uses less digits than its factorization.
2111313002020 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 11132211 (or 11132209 counting only the distinct ones).
The product of its (nonzero) digits is 72, while the sum is 16.
Adding to 2111313002020 its reverse (202003131112), we get a palindrome (2313316133132).
The spelling of 2111313002020 in words is "two trillion, one hundred eleven billion, three hundred thirteen million, two thousand, twenty".
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