Base | Representation |
---|---|
bin | 10011101010011100… |
… | …001100110000111010 |
3 | 2000111102002010121100 |
4 | 103222130030300322 |
5 | 321214430130132 |
6 | 13411011352230 |
7 | 1345126433664 |
oct | 235234146072 |
9 | 60442063540 |
10 | 21113130042 |
11 | 8a548a2104 |
12 | 41128b2676 |
13 | 1cb61a4a74 |
14 | 1044081534 |
15 | 83884737c |
hex | 4ea70cc3a |
21113130042 has 24 divisors (see below), whose sum is σ = 48436004916. Its totient is φ = 6623726976.
The previous prime is 21113130037. The next prime is 21113130079. The reversal of 21113130042 is 24003131112.
It can be written as a sum of positive squares in 2 ways, for example, as 20283171561 + 829958481 = 142419^2 + 28809^2 .
It is a Harshad number since it is a multiple of its sum of digits (18).
It is a junction number, because it is equal to n+sod(n) for n = 21113129997 and 21113130024.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 34498273 + ... + 34498884.
Almost surely, 221113130042 is an apocalyptic number.
21113130042 is an abundant number, since it is smaller than the sum of its proper divisors (27322874874).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
21113130042 is a wasteful number, since it uses less digits than its factorization.
21113130042 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 68997182 (or 68997179 counting only the distinct ones).
The product of its (nonzero) digits is 144, while the sum is 18.
Adding to 21113130042 its reverse (24003131112), we get a palindrome (45116261154).
The spelling of 21113130042 in words is "twenty-one billion, one hundred thirteen million, one hundred thirty thousand, forty-two".
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