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21113130042 = 2321768997157
BaseRepresentation
bin10011101010011100…
…001100110000111010
32000111102002010121100
4103222130030300322
5321214430130132
613411011352230
71345126433664
oct235234146072
960442063540
1021113130042
118a548a2104
1241128b2676
131cb61a4a74
141044081534
1583884737c
hex4ea70cc3a

21113130042 has 24 divisors (see below), whose sum is σ = 48436004916. Its totient is φ = 6623726976.

The previous prime is 21113130037. The next prime is 21113130079. The reversal of 21113130042 is 24003131112.

It can be written as a sum of positive squares in 2 ways, for example, as 20283171561 + 829958481 = 142419^2 + 28809^2 .

It is a Harshad number since it is a multiple of its sum of digits (18).

It is a junction number, because it is equal to n+sod(n) for n = 21113129997 and 21113130024.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 34498273 + ... + 34498884.

Almost surely, 221113130042 is an apocalyptic number.

21113130042 is an abundant number, since it is smaller than the sum of its proper divisors (27322874874).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

21113130042 is a wasteful number, since it uses less digits than its factorization.

21113130042 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 68997182 (or 68997179 counting only the distinct ones).

The product of its (nonzero) digits is 144, while the sum is 18.

Adding to 21113130042 its reverse (24003131112), we get a palindrome (45116261154).

The spelling of 21113130042 in words is "twenty-one billion, one hundred thirteen million, one hundred thirty thousand, forty-two".

Divisors: 1 2 3 6 9 17 18 34 51 102 153 306 68997157 137994314 206991471 413982942 620974413 1172951669 1241948826 2345903338 3518855007 7037710014 10556565021 21113130042