Search a number
-
+
211132560503677 is a prime number
BaseRepresentation
bin110000000000011000100001…
…010001001111001101111101
31000200120002001011021001020011
4300000120201101033031331
5210133143440442104202
62025012543112423221
762320552446266611
oct6000304121171575
91020502034231204
10211132560503677
11613008a820a72a
121b81aaa33a7b11
1390a693abac197
143a1cc28745341
151962098289bd7
hexc0062144f37d

211132560503677 has 2 divisors, whose sum is σ = 211132560503678. Its totient is φ = 211132560503676.

The previous prime is 211132560503593. The next prime is 211132560503737. The reversal of 211132560503677 is 776305065231112.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 108418511081241 + 102714049422436 = 10412421^2 + 10134794^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-211132560503677 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 211132560503677.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (211132560506677) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105566280251838 + 105566280251839.

It is an arithmetic number, because the mean of its divisors is an integer number (105566280251839).

Almost surely, 2211132560503677 is an apocalyptic number.

It is an amenable number.

211132560503677 is a deficient number, since it is larger than the sum of its proper divisors (1).

211132560503677 is an equidigital number, since it uses as much as digits as its factorization.

211132560503677 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1587600, while the sum is 49.

The spelling of 211132560503677 in words is "two hundred eleven trillion, one hundred thirty-two billion, five hundred sixty million, five hundred three thousand, six hundred seventy-seven".