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211132560507613 is a prime number
BaseRepresentation
bin110000000000011000100001…
…010001010000001011011101
31000200120002001011021020121221
4300000120201101100023131
5210133143440442220423
62025012543112453341
762320552446314233
oct6000304121201335
91020502034236557
10211132560507613
11613008a8212688
121b81aaa33aa251
1390a693abb0c04
143a1cc28746953
15196209828ae5d
hexc006214502dd

211132560507613 has 2 divisors, whose sum is σ = 211132560507614. Its totient is φ = 211132560507612.

The previous prime is 211132560507569. The next prime is 211132560507619. The reversal of 211132560507613 is 316705065231112.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 173964967818084 + 37167592689529 = 13189578^2 + 6096523^2 .

It is a cyclic number.

It is not a de Polignac number, because 211132560507613 - 225 = 211132526953181 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 211132560507613.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (211132560507619) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105566280253806 + 105566280253807.

It is an arithmetic number, because the mean of its divisors is an integer number (105566280253807).

Almost surely, 2211132560507613 is an apocalyptic number.

It is an amenable number.

211132560507613 is a deficient number, since it is larger than the sum of its proper divisors (1).

211132560507613 is an equidigital number, since it uses as much as digits as its factorization.

211132560507613 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 226800, while the sum is 43.

The spelling of 211132560507613 in words is "two hundred eleven trillion, one hundred thirty-two billion, five hundred sixty million, five hundred seven thousand, six hundred thirteen".