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211133123232113 is a prime number
BaseRepresentation
bin110000000000011001000010…
…110011111000000101110001
31000200120010111101010121112002
4300000121002303320011301
5210133201114021411423
62025013115013543345
762320602421353365
oct6000310263700561
91020503441117462
10211133123232113
1161301066920955
121b81b01b944b55
1390a69ca6580a4
143a1cc7d3892a5
1519620cc894228
hexc00642cf8171

211133123232113 has 2 divisors, whose sum is σ = 211133123232114. Its totient is φ = 211133123232112.

The previous prime is 211133123232107. The next prime is 211133123232127. The reversal of 211133123232113 is 311232321331112.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 134104205033569 + 77028918198544 = 11580337^2 + 8776612^2 .

It is a cyclic number.

It is not a de Polignac number, because 211133123232113 - 218 = 211133122969969 is a prime.

It is a super-2 number, since 2×2111331232321132 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (211133123238113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105566561616056 + 105566561616057.

It is an arithmetic number, because the mean of its divisors is an integer number (105566561616057).

Almost surely, 2211133123232113 is an apocalyptic number.

It is an amenable number.

211133123232113 is a deficient number, since it is larger than the sum of its proper divisors (1).

211133123232113 is an equidigital number, since it uses as much as digits as its factorization.

211133123232113 is an evil number, because the sum of its binary digits is even.

The product of its digits is 3888, while the sum is 29.

Adding to 211133123232113 its reverse (311232321331112), we get a palindrome (522365444563225).

The spelling of 211133123232113 in words is "two hundred eleven trillion, one hundred thirty-three billion, one hundred twenty-three million, two hundred thirty-two thousand, one hundred thirteen".