Base | Representation |
---|---|
bin | 110000000000011001000010… |
… | …110011111000000101111111 |
3 | 1000200120010111101010121112121 |
4 | 300000121002303320011333 |
5 | 210133201114021412002 |
6 | 2025013115013543411 |
7 | 62320602421353415 |
oct | 6000310263700577 |
9 | 1020503441117477 |
10 | 211133123232127 |
11 | 61301066920968 |
12 | 1b81b01b944b67 |
13 | 90a69ca6580b5 |
14 | 3a1cc7d3892b5 |
15 | 19620cc894237 |
hex | c00642cf817f |
211133123232127 has 2 divisors, whose sum is σ = 211133123232128. Its totient is φ = 211133123232126.
The previous prime is 211133123232113. The next prime is 211133123232151. The reversal of 211133123232127 is 721232321331112.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 211133123232127 - 211 = 211133123230079 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 211133123232092 and 211133123232101.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (211133123232107) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105566561616063 + 105566561616064.
It is an arithmetic number, because the mean of its divisors is an integer number (105566561616064).
Almost surely, 2211133123232127 is an apocalyptic number.
211133123232127 is a deficient number, since it is larger than the sum of its proper divisors (1).
211133123232127 is an equidigital number, since it uses as much as digits as its factorization.
211133123232127 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 18144, while the sum is 34.
Adding to 211133123232127 its reverse (721232321331112), we get a palindrome (932365444563239).
The spelling of 211133123232127 in words is "two hundred eleven trillion, one hundred thirty-three billion, one hundred twenty-three million, two hundred thirty-two thousand, one hundred twenty-seven".
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