Base | Representation |
---|---|
bin | 11110101110010101001… |
… | …100110100111011001111 |
3 | 21110211201100212000202201 |
4 | 132232111030310323033 |
5 | 234043002010010111 |
6 | 4253533234302331 |
7 | 305352530553154 |
oct | 36562514647317 |
9 | 7424640760681 |
10 | 2111332110031 |
11 | 744457a2a981 |
12 | 2a1234a279a7 |
13 | 124136a2c761 |
14 | 7429095222b |
15 | 39dc20096c1 |
hex | 1eb95334ecf |
2111332110031 has 2 divisors, whose sum is σ = 2111332110032. Its totient is φ = 2111332110030.
The previous prime is 2111332110001. The next prime is 2111332110053. The reversal of 2111332110031 is 1300112331112.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2111332110031 - 213 = 2111332101839 is a prime.
It is a super-2 number, since 2×21113321100312 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 2111332109990 and 2111332110008.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2111332110001) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1055666055015 + 1055666055016.
It is an arithmetic number, because the mean of its divisors is an integer number (1055666055016).
Almost surely, 22111332110031 is an apocalyptic number.
2111332110031 is a deficient number, since it is larger than the sum of its proper divisors (1).
2111332110031 is an equidigital number, since it uses as much as digits as its factorization.
2111332110031 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 108, while the sum is 19.
Adding to 2111332110031 its reverse (1300112331112), we get a palindrome (3411444441143).
The spelling of 2111332110031 in words is "two trillion, one hundred eleven billion, three hundred thirty-two million, one hundred ten thousand, thirty-one".
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