Base | Representation |
---|---|
bin | 10011101010011101… |
… | …010001011011111101 |
3 | 2000111102121102110020 |
4 | 103222131101123331 |
5 | 321220013130300 |
6 | 13411021402353 |
7 | 1345132015026 |
oct | 235235213375 |
9 | 60442542406 |
10 | 21113411325 |
11 | 8a54a74476 |
12 | 4112a093b9 |
13 | 1cb6272ac6 |
14 | 1044115c4d |
15 | 8388a08a0 |
hex | 4ea7516fd |
21113411325 has 24 divisors (see below), whose sum is σ = 36744746400. Its totient is φ = 10667828160.
The previous prime is 21113411251. The next prime is 21113411327. The reversal of 21113411325 is 52311431112.
It is not a de Polignac number, because 21113411325 - 211 = 21113409277 is a prime.
It is a super-2 number, since 2×211134113252 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 21113411295 and 21113411304.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (21113411327) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 7406790 + ... + 7409639.
It is an arithmetic number, because the mean of its divisors is an integer number (1531031100).
Almost surely, 221113411325 is an apocalyptic number.
21113411325 is a gapful number since it is divisible by the number (25) formed by its first and last digit.
It is an amenable number.
21113411325 is a deficient number, since it is larger than the sum of its proper divisors (15631335075).
21113411325 is a wasteful number, since it uses less digits than its factorization.
21113411325 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 14816461 (or 14816456 counting only the distinct ones).
The product of its digits is 720, while the sum is 24.
Adding to 21113411325 its reverse (52311431112), we get a palindrome (73424842437).
The spelling of 21113411325 in words is "twenty-one billion, one hundred thirteen million, four hundred eleven thousand, three hundred twenty-five".
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