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2111343323311 is a prime number
BaseRepresentation
bin11110101110010101110…
…111100110100010101111
321110211202010221201111101
4132232111313212202233
5234043012342321221
64253534314503531
7305353025065015
oct36562567464257
97424663851441
102111343323311
11744463299652
122a1238734ba7
13124139157631
14742922308b5
1539dc2ec1d91
hex1eb95de68af

2111343323311 has 2 divisors, whose sum is σ = 2111343323312. Its totient is φ = 2111343323310.

The previous prime is 2111343323293. The next prime is 2111343323381. The reversal of 2111343323311 is 1133233431112.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 2111343323311 - 215 = 2111343290543 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 2111343323311.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2111343323381) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1055671661655 + 1055671661656.

It is an arithmetic number, because the mean of its divisors is an integer number (1055671661656).

Almost surely, 22111343323311 is an apocalyptic number.

2111343323311 is a deficient number, since it is larger than the sum of its proper divisors (1).

2111343323311 is an equidigital number, since it uses as much as digits as its factorization.

2111343323311 is an evil number, because the sum of its binary digits is even.

The product of its digits is 3888, while the sum is 28.

Adding to 2111343323311 its reverse (1133233431112), we get a palindrome (3244576754423).

The spelling of 2111343323311 in words is "two trillion, one hundred eleven billion, three hundred forty-three million, three hundred twenty-three thousand, three hundred eleven".