Base | Representation |
---|---|
bin | 1100010010100011111… |
… | …1110011110100001101 |
3 | 202011222210102222011201 |
4 | 3010220333303310031 |
5 | 11424404122312303 |
6 | 240555200545501 |
7 | 21153163462612 |
oct | 3045077636415 |
9 | 664883388151 |
10 | 211141213453 |
11 | 815a978a825 |
12 | 34b06922291 |
13 | 16bab58a281 |
14 | a30da30509 |
15 | 575b60981d |
hex | 3128ff3d0d |
211141213453 has 2 divisors, whose sum is σ = 211141213454. Its totient is φ = 211141213452.
The previous prime is 211141213427. The next prime is 211141213501. The reversal of 211141213453 is 354312141112.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 196374832164 + 14766381289 = 443142^2 + 121517^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-211141213453 is a prime.
It is a super-2 number, since 2×2111412134532 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (211141213553) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105570606726 + 105570606727.
It is an arithmetic number, because the mean of its divisors is an integer number (105570606727).
Almost surely, 2211141213453 is an apocalyptic number.
It is an amenable number.
211141213453 is a deficient number, since it is larger than the sum of its proper divisors (1).
211141213453 is an equidigital number, since it uses as much as digits as its factorization.
211141213453 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 2880, while the sum is 28.
Adding to 211141213453 its reverse (354312141112), we get a palindrome (565453354565).
The spelling of 211141213453 in words is "two hundred eleven billion, one hundred forty-one million, two hundred thirteen thousand, four hundred fifty-three".
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