Base | Representation |
---|---|
bin | 10011101010100000… |
… | …010010010000101101 |
3 | 2000111111002112212101 |
4 | 103222200102100231 |
5 | 321220213414013 |
6 | 13411050335101 |
7 | 1345141514464 |
oct | 235240222055 |
9 | 60444075771 |
10 | 21114201133 |
11 | 8a55463903 |
12 | 411312a491 |
13 | 1cb648b44c |
14 | 104427d9db |
15 | 8389a98dd |
hex | 4ea81242d |
21114201133 has 2 divisors, whose sum is σ = 21114201134. Its totient is φ = 21114201132.
The previous prime is 21114201083. The next prime is 21114201167. The reversal of 21114201133 is 33110241112.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 20601722089 + 512479044 = 143533^2 + 22638^2 .
It is a cyclic number.
It is not a de Polignac number, because 21114201133 - 29 = 21114200621 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 21114201133.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (21114201233) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10557100566 + 10557100567.
It is an arithmetic number, because the mean of its divisors is an integer number (10557100567).
Almost surely, 221114201133 is an apocalyptic number.
It is an amenable number.
21114201133 is a deficient number, since it is larger than the sum of its proper divisors (1).
21114201133 is an equidigital number, since it uses as much as digits as its factorization.
21114201133 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 144, while the sum is 19.
Adding to 21114201133 its reverse (33110241112), we get a palindrome (54224442245).
The spelling of 21114201133 in words is "twenty-one billion, one hundred fourteen million, two hundred one thousand, one hundred thirty-three".
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