Base | Representation |
---|---|
bin | 1100010010100100001… |
… | …1001101010110000011 |
3 | 202011222212010020101122 |
4 | 3010221003031112003 |
5 | 11424404334320301 |
6 | 240555232022455 |
7 | 21153204163355 |
oct | 3045103152603 |
9 | 664885106348 |
10 | 211142104451 |
11 | 815aa239193 |
12 | 34b07091a2b |
13 | 16bab80c9a5 |
14 | a30dbc30d5 |
15 | 575b73381b |
hex | 31290cd583 |
211142104451 has 2 divisors, whose sum is σ = 211142104452. Its totient is φ = 211142104450.
The previous prime is 211142104421. The next prime is 211142104463. The reversal of 211142104451 is 154401241112.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-211142104451 is a prime.
It is a super-2 number, since 2×2111421044512 (a number of 23 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 211142104451.
It is not a weakly prime, because it can be changed into another prime (211142104421) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105571052225 + 105571052226.
It is an arithmetic number, because the mean of its divisors is an integer number (105571052226).
Almost surely, 2211142104451 is an apocalyptic number.
211142104451 is a deficient number, since it is larger than the sum of its proper divisors (1).
211142104451 is an equidigital number, since it uses as much as digits as its factorization.
211142104451 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1280, while the sum is 26.
Adding to 211142104451 its reverse (154401241112), we get a palindrome (365543345563).
The spelling of 211142104451 in words is "two hundred eleven billion, one hundred forty-two million, one hundred four thousand, four hundred fifty-one".
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