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21114304331 is a prime number
BaseRepresentation
bin10011101010100000…
…101011011101001011
32000111111021210102112
4103222200223131023
5321220230214311
613411052452535
71345142424401
oct235240533513
960444253375
1021114304331
118a5552439a
12411317a14b
131cb64c6403
1410442a9471
158389ca28b
hex4ea82b74b

21114304331 has 2 divisors, whose sum is σ = 21114304332. Its totient is φ = 21114304330.

The previous prime is 21114304303. The next prime is 21114304333. The reversal of 21114304331 is 13340341112.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 21114304331 - 222 = 21110110027 is a prime.

It is a super-2 number, since 2×211143043312 (a number of 21 digits) contains 22 as substring.

Together with 21114304333, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 21114304297 and 21114304306.

It is not a weakly prime, because it can be changed into another prime (21114304333) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10557152165 + 10557152166.

It is an arithmetic number, because the mean of its divisors is an integer number (10557152166).

Almost surely, 221114304331 is an apocalyptic number.

21114304331 is a deficient number, since it is larger than the sum of its proper divisors (1).

21114304331 is an equidigital number, since it uses as much as digits as its factorization.

21114304331 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 864, while the sum is 23.

Adding to 21114304331 its reverse (13340341112), we get a palindrome (34454645443).

The spelling of 21114304331 in words is "twenty-one billion, one hundred fourteen million, three hundred four thousand, three hundred thirty-one".