Base | Representation |
---|---|
bin | 111110111011001… |
… | …1110100110101010 |
3 | 12110011000220202001 |
4 | 1331312132212222 |
5 | 13311011330010 |
6 | 545303201214 |
7 | 103215612502 |
oct | 17566364652 |
9 | 5404026661 |
10 | 2111433130 |
11 | 993937a64 |
12 | 4ab14620a |
13 | 278591b21 |
14 | 1605c4a02 |
15 | c5574c3a |
hex | 7dd9e9aa |
2111433130 has 32 divisors (see below), whose sum is σ = 3826497024. Its totient is φ = 838833216.
The previous prime is 2111433113. The next prime is 2111433187. The reversal of 2111433130 is 313341112.
2111433130 is digitally balanced in base 6, because in such base it contains all the possibile digits an equal number of times.
It is a junction number, because it is equal to n+sod(n) for n = 2111433098 and 2111433107.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1308204 + ... + 1309816.
It is an arithmetic number, because the mean of its divisors is an integer number (119578032).
Almost surely, 22111433130 is an apocalyptic number.
2111433130 is a deficient number, since it is larger than the sum of its proper divisors (1715063894).
2111433130 is a wasteful number, since it uses less digits than its factorization.
2111433130 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2430.
The product of its (nonzero) digits is 216, while the sum is 19.
The square root of 2111433130 is about 45950.3332958533. Note that the first 3 decimals coincide. The cubic root of 2111433130 is about 1282.8989329020.
Adding to 2111433130 its reverse (313341112), we get a palindrome (2424774242).
It can be divided in two parts, 211 and 1433130, that added together give a palindrome (1433341).
The spelling of 2111433130 in words is "two billion, one hundred eleven million, four hundred thirty-three thousand, one hundred thirty".
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