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211162108959653 is a prime number
BaseRepresentation
bin110000000000110100000010…
…011111101001101110100101
31000200122220022102220010122112
4300000310002133221232211
5210134134444343202103
62025034311134410405
762322646624105565
oct6000640237515645
91020586272803575
10211162108959653
1161312390582a85
121b82476b060a05
1390a9669856867
143a2042cc0cda5
151962c2741ccd8
hexc00d027e9ba5

211162108959653 has 2 divisors, whose sum is σ = 211162108959654. Its totient is φ = 211162108959652.

The previous prime is 211162108959577. The next prime is 211162108959679. The reversal of 211162108959653 is 356959801261112.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 148258921050244 + 62903187909409 = 12176162^2 + 7931153^2 .

It is a cyclic number.

It is not a de Polignac number, because 211162108959653 - 228 = 211161840524197 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 211162108959592 and 211162108959601.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (211162108959253) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105581054479826 + 105581054479827.

It is an arithmetic number, because the mean of its divisors is an integer number (105581054479827).

Almost surely, 2211162108959653 is an apocalyptic number.

It is an amenable number.

211162108959653 is a deficient number, since it is larger than the sum of its proper divisors (1).

211162108959653 is an equidigital number, since it uses as much as digits as its factorization.

211162108959653 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6998400, while the sum is 59.

The spelling of 211162108959653 in words is "two hundred eleven trillion, one hundred sixty-two billion, one hundred eight million, nine hundred fifty-nine thousand, six hundred fifty-three".