Base | Representation |
---|---|
bin | 1001100110100100100010… |
… | …11110011110110100111111 |
3 | 2202202201101012000202100011 |
4 | 10303102101132132310333 |
5 | 10231433042434222142 |
6 | 112524441450044051 |
7 | 4306421360505046 |
oct | 463222136366477 |
9 | 82681335022304 |
10 | 21116499914047 |
11 | 680150377172a |
12 | 2450629119627 |
13 | ba237b59a155 |
14 | 530088c2955d |
15 | 26944e17a417 |
hex | 13349179ed3f |
21116499914047 has 2 divisors, whose sum is σ = 21116499914048. Its totient is φ = 21116499914046.
The previous prime is 21116499913973. The next prime is 21116499914051. The reversal of 21116499914047 is 74041999461112.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 21116499914047 - 231 = 21114352430399 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 21116499913982 and 21116499914000.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (21116499944047) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10558249957023 + 10558249957024.
It is an arithmetic number, because the mean of its divisors is an integer number (10558249957024).
Almost surely, 221116499914047 is an apocalyptic number.
21116499914047 is a deficient number, since it is larger than the sum of its proper divisors (1).
21116499914047 is an equidigital number, since it uses as much as digits as its factorization.
21116499914047 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3919104, while the sum is 58.
The spelling of 21116499914047 in words is "twenty-one trillion, one hundred sixteen billion, four hundred ninety-nine million, nine hundred fourteen thousand, forty-seven".
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