Base | Representation |
---|---|
bin | 11110101110110001000… |
… | …101111111101011101101 |
3 | 21110212220222102102102202 |
4 | 132232301011333223231 |
5 | 234044431310044013 |
6 | 4254051512431245 |
7 | 305400242341331 |
oct | 36566105775355 |
9 | 7425828372382 |
10 | 2111800081133 |
11 | 744678100556 |
12 | 2a13456a8525 |
13 | 1241ac97c232 |
14 | 742d6b6b7c1 |
15 | 39ded147858 |
hex | 1ebb117faed |
2111800081133 has 2 divisors, whose sum is σ = 2111800081134. Its totient is φ = 2111800081132.
The previous prime is 2111800081087. The next prime is 2111800081141. The reversal of 2111800081133 is 3311800081112.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1996690519849 + 115109561284 = 1413043^2 + 339278^2 .
It is a cyclic number.
It is not a de Polignac number, because 2111800081133 - 210 = 2111800080109 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 2111800081096 and 2111800081105.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2111800081933) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1055900040566 + 1055900040567.
It is an arithmetic number, because the mean of its divisors is an integer number (1055900040567).
Almost surely, 22111800081133 is an apocalyptic number.
It is an amenable number.
2111800081133 is a deficient number, since it is larger than the sum of its proper divisors (1).
2111800081133 is an equidigital number, since it uses as much as digits as its factorization.
2111800081133 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1152, while the sum is 29.
The spelling of 2111800081133 in words is "two trillion, one hundred eleven billion, eight hundred million, eighty-one thousand, one hundred thirty-three".
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