Base | Representation |
---|---|
bin | 10011101010110110… |
… | …011010000010010111 |
3 | 2000111220000011121211 |
4 | 103222312122002113 |
5 | 321223210001101 |
6 | 13411414522251 |
7 | 1345242016315 |
oct | 235266320227 |
9 | 60456004554 |
10 | 21120000151 |
11 | 8a58764788 |
12 | 4115066387 |
13 | 1cb773bb13 |
14 | 1044d4d0b5 |
15 | 839252c51 |
hex | 4ead9a097 |
21120000151 has 2 divisors, whose sum is σ = 21120000152. Its totient is φ = 21120000150.
The previous prime is 21120000131. The next prime is 21120000191. The reversal of 21120000151 is 15100002112.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 21120000151 - 29 = 21119999639 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (21120000131) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10560000075 + 10560000076.
It is an arithmetic number, because the mean of its divisors is an integer number (10560000076).
Almost surely, 221120000151 is an apocalyptic number.
21120000151 is a deficient number, since it is larger than the sum of its proper divisors (1).
21120000151 is an equidigital number, since it uses as much as digits as its factorization.
21120000151 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 20, while the sum is 13.
Adding to 21120000151 its reverse (15100002112), we get a palindrome (36220002263).
The spelling of 21120000151 in words is "twenty-one billion, one hundred twenty million, one hundred fifty-one", and thus it is an aban number.
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