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21120011113 is a prime number
BaseRepresentation
bin10011101010110110…
…011100101101101001
32000111220000201122211
4103222312130231221
5321223210323423
613411415045121
71345242063265
oct235266345551
960456021584
1021120011113
118a58771a43
1241150707a1
131cb7743ac6
141044d530a5
1583925610d
hex4ead9cb69

21120011113 has 2 divisors, whose sum is σ = 21120011114. Its totient is φ = 21120011112.

The previous prime is 21120011093. The next prime is 21120011153. The reversal of 21120011113 is 31111002112.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 14030876304 + 7089134809 = 118452^2 + 84197^2 .

It is a cyclic number.

It is not a de Polignac number, because 21120011113 - 29 = 21120010601 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 21120011093 and 21120011102.

It is not a weakly prime, because it can be changed into another prime (21120011153) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10560005556 + 10560005557.

It is an arithmetic number, because the mean of its divisors is an integer number (10560005557).

Almost surely, 221120011113 is an apocalyptic number.

It is an amenable number.

21120011113 is a deficient number, since it is larger than the sum of its proper divisors (1).

21120011113 is an equidigital number, since it uses as much as digits as its factorization.

21120011113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 12, while the sum is 13.

Adding to 21120011113 its reverse (31111002112), we get a palindrome (52231013225).

Subtracting 21120011113 from its reverse (31111002112), we obtain a palindrome (9990990999).

The spelling of 21120011113 in words is "twenty-one billion, one hundred twenty million, eleven thousand, one hundred thirteen".