211200201219983 has 2 divisors, whose sum is σ = 211200201219984. Its totient is φ = 211200201219982.

The previous prime is 211200201219979. The next prime is 211200201220003. The reversal of 211200201219983 is 389912102002112.

211200201219983 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 211200201219983 - 2² = 211200201219979 is a prime.

It is a super-2 number, since 2×211200201219983² (a number of 29 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 211200201219983.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (211200201219913) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105600100609991 + 105600100609992.

It is an arithmetic number, because the mean of its divisors is an integer number (105600100609992).

Almost surely, 2^{211200201219983} is an apocalyptic number.

211200201219983 is a deficient number, since it is larger than the sum of its proper divisors (1).

211200201219983 is an equidigital number, since it uses as much as digits as its factorization.

211200201219983 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 31104, while the sum is 41.

The spelling of 211200201219983 in words is "two hundred eleven trillion, two hundred billion, two hundred one million, two hundred nineteen thousand, nine hundred eighty-three".