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2112012012041 is a prime number
BaseRepresentation
bin11110101110111101101…
…110011100101000001001
321110220110202012121222122
4132232331232130220021
5234100400033341131
64254124523101025
7305405424616601
oct36567556345011
97426422177878
102112012012041
117447767a2368
122a13a4671775
13124214852c39
1474316d77c01
1539e11a5bd7b
hex1ebbdb9ca09

2112012012041 has 2 divisors, whose sum is σ = 2112012012042. Its totient is φ = 2112012012040.

The previous prime is 2112012012029. The next prime is 2112012012113. The reversal of 2112012012041 is 1402102102112.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1642231998016 + 469780014025 = 1281496^2 + 685405^2 .

It is a cyclic number.

It is not a de Polignac number, because 2112012012041 - 214 = 2112011995657 is a prime.

It is not a weakly prime, because it can be changed into another prime (2112012012241) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1056006006020 + 1056006006021.

It is an arithmetic number, because the mean of its divisors is an integer number (1056006006021).

Almost surely, 22112012012041 is an apocalyptic number.

It is an amenable number.

2112012012041 is a deficient number, since it is larger than the sum of its proper divisors (1).

2112012012041 is an equidigital number, since it uses as much as digits as its factorization.

2112012012041 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 64, while the sum is 17.

Adding to 2112012012041 its reverse (1402102102112), we get a palindrome (3514114114153).

The spelling of 2112012012041 in words is "two trillion, one hundred twelve billion, twelve million, twelve thousand, forty-one".