Base | Representation |
---|---|
bin | 110000000001011000011101… |
… | …000111000101101110000000 |
3 | 1000200210122020110210112001021 |
4 | 300001120131013011232000 |
5 | 210140310034303224300 |
6 | 2025104255130115224 |
7 | 62325532606212526 |
oct | 6001303507055600 |
9 | 1020718213715037 |
10 | 211201210211200 |
11 | 61327a26184000 |
12 | 1b830261b7bb14 |
13 | 90b025b6602b1 |
14 | 3a2229bca8316 |
15 | 1963c65073d1a |
hex | c0161d1c5b80 |
211201210211200 has 576 divisors, whose sum is σ = 579724434123120. Its totient is φ = 76024396800000.
The previous prime is 211201210211149. The next prime is 211201210211207. The reversal of 211201210211200 is 2112012102112.
It is a super-2 number, since 2×2112012102112002 (a number of 29 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (16).
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (211201210211207) by changing a digit.
It is a polite number, since it can be written in 71 ways as a sum of consecutive naturals, for example, 43448096770 + ... + 43448101630.
Almost surely, 2211201210211200 is an apocalyptic number.
211201210211200 is a gapful number since it is divisible by the number (20) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 211201210211200, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (289862217061560).
211201210211200 is an abundant number, since it is smaller than the sum of its proper divisors (368523223911920).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
211201210211200 is an equidigital number, since it uses as much as digits as its factorization.
211201210211200 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5120 (or 4980 counting only the distinct ones).
The product of its (nonzero) digits is 32, while the sum is 16.
Adding to 211201210211200 its reverse (2112012102112), we get a palindrome (213313222313312).
211201210211200 divided by its reverse (2112012102112) gives a square (100 = 102).
The spelling of 211201210211200 in words is "two hundred eleven trillion, two hundred one billion, two hundred ten million, two hundred eleven thousand, two hundred".
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