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2112012102133 is a prime number
BaseRepresentation
bin11110101110111101101…
…110110010100111110101
321110220110202101012120101
4132232331232302213311
5234100400044232013
64254124525034101
7305405425443343
oct36567556624765
97426422335511
102112012102133
1174477685401a
122a13a46b5931
13124214884c4b
1474316d9c993
1539e11a788dd
hex1ebbdbb29f5

2112012102133 has 2 divisors, whose sum is σ = 2112012102134. Its totient is φ = 2112012102132.

The previous prime is 2112012102121. The next prime is 2112012102203. The reversal of 2112012102133 is 3312012102112.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1809113771089 + 302898331044 = 1345033^2 + 550362^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-2112012102133 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 2112012102133.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2112012102113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1056006051066 + 1056006051067.

It is an arithmetic number, because the mean of its divisors is an integer number (1056006051067).

Almost surely, 22112012102133 is an apocalyptic number.

It is an amenable number.

2112012102133 is a deficient number, since it is larger than the sum of its proper divisors (1).

2112012102133 is an equidigital number, since it uses as much as digits as its factorization.

2112012102133 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 144, while the sum is 19.

Adding to 2112012102133 its reverse (3312012102112), we get a palindrome (5424024204245).

The spelling of 2112012102133 in words is "two trillion, one hundred twelve billion, twelve million, one hundred two thousand, one hundred thirty-three".