Base | Representation |
---|---|
bin | 1100010010110010100… |
… | …1010001001101000101 |
3 | 202012011001121020200201 |
4 | 3010230221101031011 |
5 | 11430020304212011 |
6 | 241005224410501 |
7 | 21154535615221 |
oct | 3045451211505 |
9 | 665131536621 |
10 | 211202413381 |
11 | 81630290183 |
12 | 34b23316a31 |
13 | 16bbb16744b |
14 | a317c01781 |
15 | 5761b97cc1 |
hex | 312ca51345 |
211202413381 has 2 divisors, whose sum is σ = 211202413382. Its totient is φ = 211202413380.
The previous prime is 211202413337. The next prime is 211202413391. The reversal of 211202413381 is 183314202112.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 188230161025 + 22972252356 = 433855^2 + 151566^2 .
It is a cyclic number.
It is not a de Polignac number, because 211202413381 - 229 = 210665542469 is a prime.
It is a super-2 number, since 2×2112024133812 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (211202413391) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105601206690 + 105601206691.
It is an arithmetic number, because the mean of its divisors is an integer number (105601206691).
Almost surely, 2211202413381 is an apocalyptic number.
It is an amenable number.
211202413381 is a deficient number, since it is larger than the sum of its proper divisors (1).
211202413381 is an equidigital number, since it uses as much as digits as its factorization.
211202413381 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2304, while the sum is 28.
Adding to 211202413381 its reverse (183314202112), we get a palindrome (394516615493).
The spelling of 211202413381 in words is "two hundred eleven billion, two hundred two million, four hundred thirteen thousand, three hundred eighty-one".
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