Base | Representation |
---|---|
bin | 1001100110101011111000… |
… | …10101001110000110110101 |
3 | 2202210002112210020120021012 |
4 | 10303111330111032012311 |
5 | 10232014130133211041 |
6 | 112530332442402005 |
7 | 4306621124013026 |
oct | 463257425160665 |
9 | 82702483216235 |
10 | 21120440132021 |
11 | 680314593381a |
12 | 2451348800305 |
13 | ba28589b9b89 |
14 | 53034025ac4d |
15 | 2695d00423eb |
hex | 13357c54e1b5 |
21120440132021 has 2 divisors, whose sum is σ = 21120440132022. Its totient is φ = 21120440132020.
The previous prime is 21120440131993. The next prime is 21120440132069. The reversal of 21120440132021 is 12023104402112.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 16192262129521 + 4928178002500 = 4023961^2 + 2219950^2 .
It is a cyclic number.
It is not a de Polignac number, because 21120440132021 - 214 = 21120440115637 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (21120440182021) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10560220066010 + 10560220066011.
It is an arithmetic number, because the mean of its divisors is an integer number (10560220066011).
Almost surely, 221120440132021 is an apocalyptic number.
It is an amenable number.
21120440132021 is a deficient number, since it is larger than the sum of its proper divisors (1).
21120440132021 is an equidigital number, since it uses as much as digits as its factorization.
21120440132021 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 768, while the sum is 23.
Adding to 21120440132021 its reverse (12023104402112), we get a palindrome (33143544534133).
The spelling of 21120440132021 in words is "twenty-one trillion, one hundred twenty billion, four hundred forty million, one hundred thirty-two thousand, twenty-one".
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