Base | Representation |
---|---|
bin | 110000000001100000101001… |
… | …100111101010100101101011 |
3 | 1000200211110221202011201101211 |
4 | 300001200221213222211223 |
5 | 210140431100030341021 |
6 | 2025112312240253551 |
7 | 62326263641246503 |
oct | 6001405147524553 |
9 | 1020743852151354 |
10 | 211210010012011 |
11 | 6133073146665a |
12 | 1b831ab90112b7 |
13 | 90b10317b671a |
14 | 3a22894888a03 |
15 | 19640cc8a73e1 |
hex | c018299ea96b |
211210010012011 has 2 divisors, whose sum is σ = 211210010012012. Its totient is φ = 211210010012010.
The previous prime is 211210010011991. The next prime is 211210010012059. The reversal of 211210010012011 is 110210010012112.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 211210010012011 - 27 = 211210010011883 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 211210010011982 and 211210010012000.
It is not a weakly prime, because it can be changed into another prime (211210710012011) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105605005006005 + 105605005006006.
It is an arithmetic number, because the mean of its divisors is an integer number (105605005006006).
Almost surely, 2211210010012011 is an apocalyptic number.
211210010012011 is a deficient number, since it is larger than the sum of its proper divisors (1).
211210010012011 is an equidigital number, since it uses as much as digits as its factorization.
211210010012011 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 8, while the sum is 13.
Adding to 211210010012011 its reverse (110210010012112), we get a palindrome (321420020024123).
The spelling of 211210010012011 in words is "two hundred eleven trillion, two hundred ten billion, ten million, twelve thousand, eleven".
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