Base | Representation |
---|---|
bin | 110000000001100000101010… |
… | …010101110100001111111111 |
3 | 1000200211110222120221101000011 |
4 | 300001200222111310033333 |
5 | 210140431111130011312 |
6 | 2025112313351444051 |
7 | 62326264146135301 |
oct | 6001405225641777 |
9 | 1020743876841004 |
10 | 211210022110207 |
11 | 6133073827a16a |
12 | 1b831b01086627 |
13 | 90b1034161313 |
14 | 3a22896317971 |
15 | 19640cd996da7 |
hex | c0182a5743ff |
211210022110207 has 2 divisors, whose sum is σ = 211210022110208. Its totient is φ = 211210022110206.
The previous prime is 211210022110183. The next prime is 211210022110279. The reversal of 211210022110207 is 702011220012112.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 211210022110207 - 243 = 202413929087999 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (211210022110807) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105605011055103 + 105605011055104.
It is an arithmetic number, because the mean of its divisors is an integer number (105605011055104).
Almost surely, 2211210022110207 is an apocalyptic number.
211210022110207 is a deficient number, since it is larger than the sum of its proper divisors (1).
211210022110207 is an equidigital number, since it uses as much as digits as its factorization.
211210022110207 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 224, while the sum is 22.
Adding to 211210022110207 its reverse (702011220012112), we get a palindrome (913221242122319).
The spelling of 211210022110207 in words is "two hundred eleven trillion, two hundred ten billion, twenty-two million, one hundred ten thousand, two hundred seven".
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